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katrin2010 [14]
3 years ago
12

Find AD. Show how you got your answer.

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0
Notice the picture below
the AD line is a bisector, cutting the 36 degrees A in half,
18 and 18 degrees each half

notice the tickmarks, the triangle is an isosceles,
if those two sides are equal, so are the angles they make
down below with the base

now, the base is 8, AD is bisecting that too, to 4 and 4

now, using the Law of Sines

\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
----------------------------\\\\
\cfrac{sin(18^o)}{4}=\cfrac{sin(72^o)}{\overline{AD}}\implies \overline{AD}=\cfrac{4\cdot sin(72^o)}{sin(18^o)}

keep in mind, the angles are in degrees, so, when taking the sines, make sure your calculator is in Degree mode

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Cual es la forma más simple al efectuar la operación indicada en la expresión (-3) (-12) ?
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Cual es la forma más simple al efectuar la operación indicada en la expresión (-3) (-12) ?  this means What is the simplest way to perform the operation indicated in the expression (-3) (-12)?

Step-by-step explanation:

Multiply -3 by -12 and get 36. hope this was helpful.

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Put these numbers in order from greatest the least 28/13 -0.4 1 6/20
tiny-mole [99]

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Step-by-step explanation:

3 0
3 years ago
If Bob sells each fish at a profit of $1.25, how much money will he have after selling all 24 fish? Show your calculation.
Aleks04 [339]

Answer:  $30

Step-by-step explanation:

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3 0
2 years ago
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Centerpieces are normally distributed with mean of 30 ounces and standard deviation of 2 ounces. The weights of the shipping box
astraxan [27]

Answer:

0.0901 = 9.01% of packages will incur such a charge

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sum of normal variables:

When we add normal variables, the mean will be the sum of the means, while the standard deviation is the square root of the sum of the variances.

Centerpieces are normally distributed with mean of 30 ounces and standard deviation of 2 ounces.

This means that \mu_C = 30, \sigma_C = 2

The weights of the shipping boxes are normally distributed with mean of 12 ounces and standard deviation of 1 ounce.

This means that \mu_S = 12, \sigma_S = 1

Suppose that centerpieces are chosen at random and packed into randomly chosen shipping boxes.

The shipment is given by the centerpice plus the shipping box. So the mean and the standard deviation of the weight are given by:

\mu = \mu_C + \mu_S = 30 + 12 = 42

\sigma = \sqrt{\sigma_C^2 + \sigma_S^2} = \sqrt{2^2 + 1^2} = \sqrt{5} = 2.236

If a package exceeds 45 ounces, an additional charge is incurred. What is the proportion of packages will incur such a charge

This proportion is 1 subtracted by the pvalue of Z when X = 45. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 42}{2.236}

Z = 1.34

Z = 1.34 has a pvalue of 0.9099

1 - 0.9099 = 0.0901

0.0901 = 9.01% of packages will incur such a charge

7 0
3 years ago
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