Answer:
There could be 0, 2, or 4 complex solutions
Step-by-step explanation:
The Fundamental Theorem of Algebra states that any polynomial with n degree will have n solutions So since the degree of the polynomial you provided has a degree of 4, that means there are 4 possible solutions. This question specifically asks for complex zeroes. Complex zeroes come in conjugate pairs, so that means if you have one complex zero, there is another complex zero which is it's conjugate. For this reason, there can only be an even number of complex zeroes. And since there's 4 possible solutions, There could be 0, 2, or 4 complex solutions
Answer:
the answer is 15 pounds less
Step 4 because where did she get the 2 there was no two hope this helps hope i am brainliest
Answer:
r= 7.14 (rounded to 2 decimal places)
Step-by-step explanation:
We have to solve this equation for the value of r. We will use distributive property and basic algebra to solve this.
Distributive property is a(b+c) = ab + ac
Now, the steps of solving are shown below:

Hence, value of r is 7.14 (rounded to 2 decimal places)