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Nookie1986 [14]
3 years ago
12

Wanda works for a large company. She and her team maintain a set of servers that support their office, and their office is conne

cted to other distant offices owned by the same company.
Which of the following is definitely true?

Wanda works inside a data center.
Wanda and her team run a WAN.
Wanda and her team run a P2P network.
Wanda and her team support a very secure network.
Computers and Technology
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

Wanda works inside a data center.

Explanation:

A data center is a place where a company stores and manages its IT operations and devices. From this place the data is distributed.

A WAN is a network that works in a large area.

A P2P network refers to computers that are connected through the internet.

A secure network refers to any network that has security measures to avoid outside attacks.

According to the definitions and considering that the excerpt says that Wanda's team maintain a set of servers that support their office, and their office is connected to other distant offices, the answer is that Wanda works inside a data center.

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Suggest names for a coding club
bulgar [2K]

Answer:

  • <u>Abstract Connoisseurs.</u>
  • <u>Hypertext Assassins.</u>
  • <u>Callback Cats.</u>
  • <u>Boolean Autocrats.</u>
  • <u>Runtime Terror.</u>

Explanation:

<em><u>Hope it's help you !!</u></em>

3 0
2 years ago
An office is facing a network issue. The technicians have determined that a virus affected the manager's computer. However, they
Margarita [4]

Answer:

The correct answer is: Bus Topology.

Explanation:

Bus Topology is a network setup where all the computers are connected to a single cable. Servers can connect easily to the network but it implies everyone connected has access to what everybody in the same network is doing. Security options are limited to no-existent under this topology.

In that case, if technicians cannot isolate a virus infection problem, it is the result of working with a bus topology where more than one computer is connected to the same network and every terminal has access to each terminal.

7 0
3 years ago
What is 11x12x12x14x15x16
ser-zykov [4K]

Answer:

11x12x12x14x15x16=5,322,240

Explanation:

11*12=132

12*14=168

15*16=240

132*168=22,176

240*22,176=5,322,240

Have a nice day! :)

4 0
2 years ago
Which of the following is a database concept that allows for storage and analysis for a dozen to billions of data points?
nydimaria [60]

Answer:

C) Storage

Explanation:

I am sure of it.

5 0
3 years ago
You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
2 years ago
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