Answer:
The program in recursion is:
def find_max(nums):
if len(nums) == 0:
return "None"
elif len(nums) == 1:
return nums[0]
else:
return max(nums[0],find_max(nums[1:]))
Explanation:
This line defines the function
def find_max(nums):
This checks if the list is empty.
if len(nums) == 0:
If yes, it returns "None"
return "None"
If the list has just one element
elif len(nums) == 1:
It returns the only element as the maximum
return nums[0]
If the list has numerous elemente
else:
The maximum is determined recursively
return max(nums[0],find_max(nums[1:]))
To the (b) part:
<em>This program does not necessarily need to be done recursively because the max built-in function can be used to determine the maximum of the list in just one line of code and it is more efficient.</em>
Answer:
// Here is SammysRentalPrice.java file
// import package
import java.util.*;
// class definition
class SammysRentalPrice
{
// main method of the class
public static void main (String[] args) throws java.lang.Exception
{
try{
// object to read value from user
Scanner scr=new Scanner(System.in);
// ask to enter rented minutes
System.out.print("enter rented minutes: ");
// read minutes
int min=scr.nextInt();
// find hours
int hour=min/60;
//reamining minutes
min=min%60;
// total cost
int cost=hour*40+min*1;
// print cost
System.out.println("total cost is: "+cost);
}catch(Exception ex){
return;}
}
}
Explanation:
Read rented minutes from user and assign it to variable "min".Find the hours from minutes and then update the remaining minutes.After this multiply hours with 40 and remaining minutes with 1.Sum them and this will be the cost of rented a sports equipment.
Output:
enter rented minutes: 145
total cost is: 105
<span>An asterisk or a superscript number.</span>
The answer is B cause you use it to make commands
Answer:
is a measurement that defines the sharpness of a display. It measures the distance between the dots used to display the image on the screen. This distance is very small and is typically measured in fractions of millimeters. The smaller the dot pitch, the sharper the picture.
