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pantera1 [17]
3 years ago
12

What 3 numbers when multiplied, equals to 4,000? Please help! Will give Brainliest!

Mathematics
2 answers:
vlada-n [284]3 years ago
7 0

Answer:

you can do (500)(4) x 2

Step-by-step explanation:

500 x 4 = 2000

2000(2) = 4000

goblinko [34]3 years ago
3 0

Answer:

5 × 10 × 80

Step-by-step explanation:

Since there are no rules imposed by your question, any three numbers whose product is 4,000 is the answer.

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My question is 9 + 12n
Aliun [14]

Answer:

3(3 +4n)

OR

9 + 12n

Step-by-step explanation:

9 + 12n

Factorize it

3(3 +4n)

OR

The answer is the same.

Since we can't add a number with a number and letter. So in that case the answer is ;

9 + 12n.

<h3>Hope it helps!!</h3><h3><em>Please mark me as the brainliest</em><em>!</em><em>!</em><em>!</em></h3>

<em>Thanks</em><em> </em><em>!</em><em>!</em><em>!</em><em>!</em>

3 0
2 years ago
Is the answer for number 3 solution or open sentence?
Katen [24]
I believe it's a solution
6 0
3 years ago
Two ratios that are equivalent to 5/7
grigory [225]

You could pick just about anything 3/8 is not the same thing as 5/7 and neither is 3/4

Something that is equivalent would be something like 10/14 or 20/28

3 0
3 years ago
Simplify (7+5)^2 divided by 4 x 3 + 9
MaRussiya [10]
((7 + 5)^2) / (4 * 3 + 9) =
(12^2) / (12 + 9) =
144 / 21 reduces to 48/7 or 6 6/7

7 0
3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
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