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Sav [38]
2 years ago
15

Find (h . g) (x) h (x) = 3x - 3 and g (x) = x2 + 3 A. 3x3 - 9 B. 3x3 - 3x2 + 9x C. 3x3 - 3x2 + 9x - 9 D. 3x3 + 3x2 + 9x - 9​

Mathematics
1 answer:
svp [43]2 years ago
8 0

Answer:

Step-by-step explanation:

(3x - 3)(x^2 + 3) = 3x^3 + 9x - 3x^2 - 9

3x^3 = 3x^2 + 9x - 9

answer is C

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Find the measurement of both complementary angles, if:
aniked [119]

We are given one angle is 3 times less than other.

Let us assume one angle measure is x degrees and another is 4x.

Because x is 3x less than 4x.            ( We can check 4x-x= 3x)

Sum of complementary angles is 90 degrees.

So, we can setup an equation

First angle measure + first angle = 90 degrees.

x+4x = 90.

Adding x and 4x, we get 5x.

So, 5x = 90.

Dividing both sides by 5, we get

5x/5 = 90.

x= 18.

So, one angle is of 18 degrees.

Another angle = 4x = 4 times 18 = 72 degrees.

So, required angles are of 18 degree and 72 degree.



8 0
3 years ago
What are the geometric means of 5 and 15
Phantasy [73]

Answer:

2√15

Step-by-step explanation:

7 0
3 years ago
12. 13. 15. Plz help
Lera25 [3.4K]
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6 0
2 years ago
Read 2 more answers
Find the sum of a finite geometric sequence from n = 1 to n = 7, using the expression −4(6)n − 1.
Verizon [17]

Answer:

<h2>-223,948</h2>

Step-by-step explanation:

The formula of a sum of terms of a gometric sequence:

S_n=a_1\cdot\dfrac{1-r^n}{1-r}

a₁ - first term

r - common ratio

We have

a_n=-4(6)^{n-1}

Calculate a₁. Put n = 1:

a_1=-4(6)^{1-1}=-4(6)^0=-4(1)=-4

Calculate the common ratio:

r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=-4(6)^{n+1-1}=-4(6)^n\\\\r=\dfrac{-4(6)^n}{-4(6)^{n-1}}=6^n:6^{n-1}\\\\\text{use}\ a^n:a^m=a^{n-m}\\\\r=6^{n-(n-1)}=6^{n-n+1}=6^1=6

\text{Substitute}\ a_1=-4,\ n=7,\ r=6:\\\\S_7=-4\cdot\dfrac{1-6^7}{1-6}=-4\cdot\dfrac{1-279936}{-5}=-4\cdot\dfrac{-279935}{-5}=(-4)(55987)\\\\S_7=-223948

7 0
3 years ago
Which property justifies this statement?
Fantom [35]
I believe its C because they distribute instead of reverse like A would be
6 0
3 years ago
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