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Helen [10]
3 years ago
11

Solve the system of equations.

Mathematics
2 answers:
ycow [4]3 years ago
7 0
The answer is letter c.
Dafna1 [17]3 years ago
4 0
C is the answer for this
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How many 3/8ths are in 3 3/4ths?
Vitek1552 [10]

Answer:

10

Step-by-step explanation:

First make the fractions the same value:

3 and 3/4s is equal to

15/4 which is 30/8s

So,

10  3/8s go into 30/8s

3 0
4 years ago
Read 2 more answers
A manufacturing company plans to coat the entire exterior of a cylindrical shipping container with a 0.075-mm layer of special r
ycow [4]

Answer:

534.07cm² * 0.35=186.9245 dollar

6 0
3 years ago
Preform the indicated operation x^3 x^2
tresset_1 [31]
Simplify the following:
x^3 x^2

x^3 x^2 = x^(3 + 2):
x^(3 + 2)
3 + 2 = 5:
Answer:  x^5
5 0
3 years ago
Read 2 more answers
Use the calculator to find the product. (1. 466 × 10–8)(5. 02 × 105) What is the coefficient of the product? What is the exponen
mestny [16]

The product of the factors in the given expression comes to be 7.35932 *10^{-3}.

The given expression is:

(1.466*10^{-8} )(5.02*10^5)

We can rewrite the given expression as

(1.466*5.02)(10^{-8} *10^5)

<h3>What is the exponent addition rule? </h3>

If we have two numbers with the same base we can write the product of the numbers as a single base followed by the addition of exponents.

a^m*a^n = a^{m+n}

1.466*5.02=7.35932

10^{-8} *10^5 = 10^{-3}....from exponent addition rule

So, (1.466*10^{-8} )(5.02*10^5)=7.35932 *10^{-3}

Therefore, the product of the factors in the given expression comes to be 7.35932 *10^{-3}.

To get more about exponents visit:

brainly.com/question/819893

6 0
2 years ago
Read 2 more answers
Write the first six terms of the geometric sequence with the first term 6 and common ratio 1/3
Alja [10]

Answer:

6, 2, 2/3, 2/9, 2/27, 2/81

Step-by-step explanation:

The nth term of a geometric progression is expressed as;

Tn  = ar^n-1

a is the first term

n is the number of terms

r is the common ratio

Given

a = 6

r = 1/3

when n = 1

T1 = 6(1/3)^1-1

T1 = 6(1/3)^0

T1 = 6

when n = 2

T2= 6(1/3)^2-1

T2= 6(1/3)^1

T2 = 2

when n = 3

T3 = 6(1/3)^3-1

T3= 6(1/3)^2

T3= 6 * 1/9

T3 = 2/3

when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

T4 = 2/9

when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

T5 = 2/27

when n = 6

T6 = 6(1/3)^6-1

T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81

6 0
3 years ago
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