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nika2105 [10]
3 years ago
15

What drug is most commonly used to incapacitate people into having non-consensual sexual experiences?

Advanced Placement (AP)
2 answers:
Serggg [28]3 years ago
8 0

The correct answer is GHB, which stands for gamma-Hydroxybutyric acid. Its chemical formula is C₄H₈O₃.

GHB or Gamma Hydroxybutyrate (C4H8O3) is a focal sensory system (CNS) depressant that is normally alluded to as a "club drug" or "date assault" sedate. GHB is mishandled by teenagers and youthful grown-ups at bars, gatherings, clubs and "raves" (throughout the night move parties), and is regularly set in mixed drinks. Elation, expanded sex drive, and peacefulness are accounted for beneficial outcomes of GHB manhandle. Negative impacts may incorporate perspiring, loss of cognizance, queasiness, fantasies, amnesia, and trance like state, among opposite reactions.

k0ka [10]3 years ago
3 0
I believe the drug which is being described above is known as GHB, which stands for <span>gamma-Hydroxybutyric acid. It creates a feeling of elation, and depresses the central nervous system in the body.</span>
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<h3>What is probability? </h3>

Probability can be defined as the likelihood of an event to occur. In statistics, the mean of the sample distribution typically shows the probability of the population.

From the parameters given:

  • The sample size (n) = 55 patients
  • Let's assume that the mean (x) = 32 (i.e. 58.2%) of the patients

The sample proportion \mathbf{\hat p} can be computed by using the expression:

\mathbf{\hat p = \dfrac{x}{n}}

\mathbf{\hat p = \dfrac{32}{55}}

\mathbf{\hat p =0.582}

If the percentage of the probability of all patients in the emergency room = 0.75

The probability that the proportion of patients who wait less than 30 minutes is 0.582 or less can be computed as:

\mathbf{( \hat P \leq 0.582) = P \Big( \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}} \leq \dfrac{0.582 - 0.75}{\sqrt{\dfrac{0.75(1-0.75)}{55}}} \Big )}

\mathbf{( \hat P \leq 0.582 )= P \Big( Z \leq \dfrac{-0.168}{\sqrt{0.003409}} \Big )}

\mathbf{( \hat P \leq 0.582) = P \Big( Z \leq -2.88 \Big )}

From the Z distribution table:

\mathbf{( \hat P \leq 0.582) = 0.00198}

\mathbf{( \hat P \leq 0.582) \simeq 0.0020}

Learn more about probability here:

brainly.com/question/24756209

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