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ella [17]
2 years ago
8

Thank you for the help

Mathematics
1 answer:
galben [10]2 years ago
8 0

Answer:

lll

Step-by-step explanation:

hope it's helpful

Most welcome

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Solve for B.<br><br> A=3B+7C
Archy [21]

Hey there!!

Given:

... A=3B+7C

Subtracting 7C on both sides:

... A-7C=3B

Dividing by B on both sides:

... (A-7C)/3=B

<em>Hope my answer helps!</em>

6 0
3 years ago
A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo
deff fn [24]

Answer:

\frac{x^2}{61}-\frac{y^2}{37}  =1

Step-by-step explanation:

The standard equation of a hyperbola is given by:

\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

\frac{x^2}{61}-\frac{y^2}{37}  =1

6 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
Find the product.<br><br> (8-3z)(8+3z)
maks197457 [2]

Step-by-step explanation:

you can open the file I gave you now. the answer is there

7 0
2 years ago
24 + 0.44x = 19 + 1.69x
lys-0071 [83]

Answer:

if it is find the value of x her it is

24 + 0.44x = 19 + 1.69x \\ collect \: like \: terms \\ 24 - 19 = 1.69x - 0.44x \\ 5 = 1.25x \\ divide \: both \: side \: by \: 1.25 \\  \frac{5}{1.25}  =  \frac{1.25x}{1.25}  \\ 4 = x \\ x = 4

6 0
3 years ago
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