X^2-3x = x(x-3)
x^2-9 = x^2 - 3^2 = (x-3)(x+3)
HCF = x-3
<span><span> Let ABC be an isosceles triangle with AB = AC. Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC). Thena)<span> </span>Triangle ABM is congruent to triangle ACM.b)<span> </span>Angle ABC = Angle ACB (base angles are equal)c)<span> </span>Angle AMB = Angle AMC = right angle.d)<span> </span>Angle BAM = angle CAM
</span></span>
ANSWER

EXPLANATION
Method 1
Vertically opposite angles are equal, therefore

This implies that,

We simplify to get,

Dividing through by 3 gives,

Also,

This implies that,

We simplify the right hand side to get,

We divide both sides both sides by 2 to get,



Method 2
Angles on straight line sums to 180°.

This implies that,




Also,






Answer:1 quarter, 2 dimes and 1 nickel, 5 nickels, 3 nickels and 1 dime
Step-by-step explanation: