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slavikrds [6]
3 years ago
13

Two mountain bikers take off from the same place at the same time. One travels north at 4 mph, and the other travels east at 3 m

ph. How far apart are they after 4 hours?
A. 14 miles
B. 20 miles
C. 28 miles
D. 5 miles
Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

20 miles (Answer B)

Step-by-step explanation:

The northbound biker travels (4 mph)(4 hr) = 16 mi, and

the eastbound biker travels (3 mph)(4 hr) = 12 mi.

They travel at right angles to one another.  Thus, the Pythagorean Theorem applies here.  The distance between the two bikers is d = √( [12 mi]^2 + [16 mi]^2 ), or √(144 + 256) mi, or √400 mi, which works out to 20 miles.

Answer B is correct.


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vlada-n [284]

Answer:

1. x = -1.5y

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Step-by-step explanation:

1) Simplifying

7x + 2y + -3x + 4y = 0

Reorder the terms:

7x + -3x + 2y + 4y = 0

Combine like terms: 7x + -3x = 4x

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Combine like terms: 2y + 4y = 6y

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Solving

4x + 6y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y' to each side of the equation.

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Combine like terms: 6y + -6y = 0

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Simplifying

x = -1.5y

2)

Common factor

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5p = 3p + 8

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Add '-3p' to each side of the equation.

5p + -3p = 8 + 3p + -3p

Combine like terms: 5p + -3p = 2p

2p = 8 + 3p + -3p

Combine like terms: 3p + -3p = 0

2p = 8 + 0

2p = 8

Divide each side by '2'.

p = 4

Simplifying

p = 4

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