Solve the given differential equation by separation of variables. csc(y) dx sec2(x) dy

How do you solve and show work for <br>624 divided by 8<br>

natali 33 [55]

pls mark as brainlist

Step-by-step explanation:

624 divided by 8 = 78

7 0

3 years ago

Read 2 more answers

Determine whether the subset of Mn,n is a subspace of Mn,n with the standard operations of matrix addition and scalar multiplica

sveta [45]

Answer:

solution is attached in the picture below

Step-by-step explanation:

8 0

3 years ago

The value of the digit in the hundreds place in the number 587,349 is 1/10 the value of the digit in the thousands place in whic

Musya8 [376]

Answer:

3000 is your answer

Step-by-step explanation:

The 3 in the hundreds place if the number 587,349 has a value of 300. This 300 is 1/10 the value of the number you're looking for, so if x is the number you're looking for, then

$300 = \frac{1}{10} x$

$300 \times 10 = \frac{1}{10} x \times 10$

$3000 = x$

x is your answer.

3 0

3 years ago

wat iz 9999999999999999999999999999999999999999999999999999999+99999999999999999999999999999999999999999999999999999999999999999

choli [55]

Ahbfiubauehfiouabcbaiu

5 0

3 years ago

A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ

ivann1987 [24]

Answer:

$p_v= P(\chi^2_{9}>11.517)=0.2419$

And on this case if we see the significance level given $\alpha=0.1$ we see that $p_v>alpha$ so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

$p_v$ represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: $O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

On this case after calculate the statistic they got: $\chi^2 = 11.517$

And in order to calculate the p value we need to find first the degrees of freedom given by:

$df=n-1=10-1=9$ , where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

$p_v= P(\chi^2_{9}>11.517)=0.2419$

And on this case if we see the significance level given $\alpha=0.1$ we see that $p_v>alpha$ so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0

3 years ago