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Rashid [163]
3 years ago
11

How much sugar should he use ?

Mathematics
1 answer:
Sonja [21]3 years ago
6 0
The answer is A. 1 1/4

You have to subtract 1 3/4 - 1/2 and get 1 1/4

Hope this helps!
You might be interested in
if one angle in a pair of vertical angles measures 36degrees and the other measures (2n-8)degrees, which is the value of n ? ple
KiRa [710]

Answer:

n = 22

Step-by-step explanation:

Since they are vertical angles they are the same.

Therefore you can put together this equation:

2n - 8 = 36

Add 8 to both sides

2n = 44

Divide by 2

n = 22

8 0
4 years ago
Find an equation of the largest sphere with center (8, 2, 9) that is contained in the first octant.
Furkat [3]
The point (8,2,9) is in the first octant.
The closest distance from the coordinate planes is the value y=2, which will therefore be the maximum radius of the required sphere.

The standard equation of a sphere with radius r and centre (u,v,w) is given by
(x-u)^2+(y-v)^2+(z-w)^2=r^2

Substituting r=2, u=8, v=2, w=9, we get the equation of the required sphere
(x-8)^2+(y-2)^2+(w-9)^2=2^2
8 0
3 years ago
What are the terms in the expression, 2 + 6 + 10b – 8a?
Nitella [24]

Answer:

Step-by-step explanation:

2(1+5b-4a)

7 0
3 years ago
A sedan will drive ten miles north, 15 miles east, 13 miles south, 15 miles west, and 22 miles north. The sedan gets 20 miles pe
jarptica [38.1K]

<u>Answer</u>:

There is enough fuel for the trip and the relative distance is 19 miles

<u>Explanation</u>:

Given Sedan drives

10 miles north

15 miles east

13 miles south

15 miles west

22 miles north

Then total distance = 10 + 15 + 13 + 15 + 22 = 75 miles

There are 5 gallons of gas left and sedan gets 20 miles per gallon

20 miles = 1 gallon

75 miles = 75/20 = 3.75 gallons

Gas left = 5 – 3.75 = 1.25 gallon

So, there is enough fuel for the trip

Relative distance = 10 (north) + 15 (east) – 13 (south) – 15 (west) + 22 (north) = 19 miles

7 0
3 years ago
A game has an expected value to you of ​$100. it costs ​$500 to​ play, but if you win you receive​ $100,000 (including your ​$50
tekilochka [14]

Let X be a random variable denoting the amount of winnings in any given round of the game. There is some probability p of winning where P(X=99,500)=p, while P(X=-500)=1-p, assuming these are the only two possible outcomes. So we have

\mathbb E[X]=\displaystyle\sum_xxP(X=x)=99,500p-500(1-p)=100

100,000p-500=100\implies p=\dfrac3{500}=0.006

8 0
3 years ago
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