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alexandr402 [8]
3 years ago
7

Find domain and range -√x-5+10

Mathematics
1 answer:
inysia [295]3 years ago
8 0
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)

But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
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explanation:

3(2x-y=-4)
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9x+3y=-3
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2(-1) - y = -4
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2 years ago
2. Every month, Jenny and Gopal ________ the orphanages in China. They have been to five orphanages so far.
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Answer:

2. A

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4. B

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6. C

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9. D

10. C

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3 years ago
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I don't know how to explain it
Lemur [1.5K]

Answer:

Sam's thinking was incorrect.

On number first we have to move 10 units from 0 in positive direction after that negative sign means move in left direction.

But we have 2 negative signs so we need to move 6 units more on positive or right direct as shown below.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
It’s a new semester! Students are grouped into three clubs, which each has 10, 4 and 5 students. In how many ways can teacher se
ozzi

Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.

So there are 3 clubs:

  • Club A, with 10 students.
  • Club B, with 4 students.
  • Club C, with 5 students.

The possible combinations of 2 students from different clubs are

  • Club A with club B
  • Club A with club C
  • Club B with club C.

The number of combinations for each of these is given by the product between the number of students in the club, so we get:

  • Club A with club B: 10*4 = 40
  • Club A with club C: 10*5 = 50
  • Club B with club C. 4*5 = 20

For a total of 40 + 50 + 20 = 110 different combinations.

This means that there are 110 different ways in which 2 students from different clubs can be selected.

If you want to learn more about combination and selections, you can read:

brainly.com/question/251701

6 0
2 years ago
Help please PLEASE IM FREAKING SERIOUS IF I DONT FINISH IT BY 9 IM DEAD ILL GIVE 50 POINTS HELP PLEASE IM ACTUA;LY FRICKIN SERRI
yuradex [85]

Answer:

1/4 i think

Step-by-step explanation:

hope this helps

if i was right pls mark brainliest

6 0
2 years ago
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