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alexandr402 [8]
3 years ago
7

Find domain and range -√x-5+10

Mathematics
1 answer:
inysia [295]3 years ago
8 0
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)

But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
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liq [111]

Answer:

x = 24

y = 19

Step-by-step explanation:

7 0
3 years ago
Help me with this 1,2,3. For each sequence, Determine with whether it appears to be arithmetic If it does find a common differen
pshichka [43]

Problem 1

<h3>Answer: Arithmetic, common difference = -4</h3>

-------------------

Explanation:

Pick any term of the sequence, and subtract off the previous term to find that,

  • term2 - term1 = -12 - (-8) = -12 + 8 = -4
  • term3 - term2 = -16 - (-12) = -16 + 12 = -4
  • term4 - term3 = -20 - (-16) = -20 + 16 = -4

Each time we get the same result, so that means we have an arithmetic sequence with common difference -4

This indicates that adding -4 to each term, or subtracting 4 from each term, will generate the next one.

Eg: term2 = term1 - 4 = -8-4 = -12.

==========================================================

Problem 2

<h3>Answer: Arithmetic, common difference = 5</h3>

-------------------

Explanation:

Similar to problem 1, this sequence is also arithmetic because we add on 5 to each term to get the next one

  • -6+5 = -1
  • -1+5 = 4
  • 4+5 = 9

Or you could subtract adjacent terms as done in problem 1, to find that the common difference is 5.

==========================================================

Problem 3

<h3>Answer: Not arithmetic</h3>

-------------------

Explanation:

Unlike the previous two problems, this sequence is not arithmetic.

We can see that

  • term2 - term1 = 12 - 3 = 9
  • term3 - term2 = 48 - 12 = 36

The gaps of 9 and 36 aren't the same. We need the same common difference between any adjacent terms to have an arithmetic sequence.

This sequence is instead geometric because

  • term2/term1 = 12/3 = 4
  • term3/term2 = 48/12 = 4
  • term4/term3 = 192/48 = 4

Each quotient is 4, showing the common ratio is 4. To find the next term, we multiply the current term by 4. So the next term after 192 would be 4*192 = 768, then 4*768 = 3072 is next, and so on.

3 0
3 years ago
3x - 5y = 14 and – 2x + 2y = 0
zubka84 [21]

Answer:

x=5.6

y=-5.6

Step-by-step explanation:

3x - 5y = 14 Equation 1

– 2x + 2y = 0 Equation 2

Simultaneous equation can be solved either through elimination method or substitution method. But we use elimination method for this question

Multiply equation 1 by -2 (the coefficient of x in equation 2) and multiply equation 2 with 3 (the coefficient of x in equation 1), so that x will have the same coefficient in the new equations, and easy to eliminate

-2(3x - 5y = 14)

-6x+10y=-28 Equation 3

3(– 2x + 2y = 0)

-6x+6y=0 Equation 4

Subtract equation 4 from 3 to eliminate x

-6x+10y=-28

-6x+6y=0

-6x-(-6x)=-6x+6x=0

10y-6y=5y

-28-0=-28

5y=-28

y=-28/5

y=-5.6

Substitute for y in equation 2

– 2x + 2y = 0

– 2x + 2(-5.6) = 0

-2x-11.2=0

-2x=11.2

x=-11.2/2

x=5.6

7 0
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Murljashka [212]

Answer:

250 bags

Step-by-step explanation:

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