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Wittaler [7]
3 years ago
9

(5, 14) and (3, 10) Rate of change = 2 Initial value =

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0

Answer:

If you do your Homework, you will hurt your teachers badly emotionally and mentally. You will break not only your teacher's heart but also their mind and soul. You will destroy you teacher's trust, respect, hope, and dreams. You will cause your teacher great sorrow and depression that might destroy their life.

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The perimeter of a square Is 176 centimeters. If the square is dilated by a scale factor of 0.75, what is the length of each sid
seropon [69]

Answer: The answer is a decimal.

Step-by-step explanation:

7 0
3 years ago
if the area of a square is 144 feet and the perimeter of the triangle is 28 feet, what is the perimeter of the room's floor?
FinnZ [79.3K]

Answer:

52+12\pi

Step-by-step explanation:

The diagram for the question is attached below

perimeter of the triangle is 28 feet

area of a square is 144 feet

Area of the square is side^2

side ^2= 144

take square root on both sides

side = 12

side of the square = 12

side is the diameter of the semicircle

Diameter = 12 , so radius = 12 divide 2 = 6

circumference of semicircle = 2\pi r=2\pi (6)=12\pi

one side of the rectangle is calculated in the perimeter of triangle and other side is calculated using circumference

perimeter of other two side = 2(12)= 24

Total perimeter = 28+24+12\pi =52+12\pi

4 0
4 years ago
SOLVE : 3|x-2|-10=11
Andru [333]

Answer:

The answer final

x1= -5; x2=9

Step-by-step explanation:

If you want me to expand on the equation leave me a comment :)

7 0
3 years ago
A farmer has a 100 ft by 200 ft rectangular field that he wants to increase by 15.5% by cultivating a strip of uniform width aro
Advocard [28]

Answer:

(a) The strip should be 5ft wide

(b) The strip around the outside field is 10ft wide.

Step-by-step explanation:

Given:

Length of the rectangular field, L= 200 ft

width of the rectangular field, w = 100 ft

Area of the rectangular field, A = 200ft x 100ft = 20000 ft^2

let the width of the strip = x

The strip around the outside field = 2x

If the field is increased by 15.5%

New area of the field = 1.155 x 20000 = 23,100 ft^2

The increase in area of the field = 3,100 ft

3,100 = New area of field - old area of the field

3100 = (200 + 2x)(100 + 2x) - 20000

3100 = 20000 + 400x 200x + 4x^2 - 20000

3100 = 600x + 4x^2

Divide through by 4

775 = 150x + x^2

x^2 + 150x - 775 = 0

Factorize

(x + 155)(x-5) = 0

x = 5 ft

The strip should be 5ft wide.

The strip around the outside field = 2 x 5 ft = 10 ft

Thus, the strip around the outside field is 10ft wide.

3 0
3 years ago
What is the slope of a line that is perpendicular to the graph of<br> y= 5x + 5?
AVprozaik [17]
-5/1 is the slope so the answer is -5 because you pick 2 points and use point slope formula or
y1-y2/x1-x2
3 0
4 years ago
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