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PolarNik [594]
3 years ago
10

Consider the diagram. Line l is a perpendicular bisector of line segment R Q. It intersects line segment R Q at point T. Line l

also contains point S. Line segment R S is 3 x + 2. Line segment S Q is 5 x minus 8. What is QS? 2 units. 5 units. 17 units. 33 units.
Mathematics
2 answers:
shtirl [24]3 years ago
8 0

Answer:

the answer is SR

Step-by-step explanation:

the answer is c i just took the test lol gimme a like and 5 stars

Whit
2 years ago
uhhhh the answer is not SR they were asking for the units for QS
Lesechka [4]3 years ago
6 0

Answer:

17 units

Step-by-step explanation:

3x + 2 = 5x - 8

10 = 2x

5 = x

5(5)-8 = 17

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The distance between the school and the airport on a map is 7.25 cm. The scale of the map is 1 cm : 12 m. What is the actual dis
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4 0
2 years ago
Read 2 more answers
Please help as soon as possible
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1 kilometer = 1000 meters so 12 kilometers = 12000 meters

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4 0
3 years ago
What is the distance between points M and N?
Free_Kalibri [48]

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

<h3>How to determine the distance between two points</h3>

In this problem we must determine the distance between two points that are part of a triangle and we can take advantage of properties of triangles to find it. First, we determine the measure of angle L by the law of the cosine:

\cos L = \frac{(19.6\,m)^{2}-(14.8\,m)^{2}-(21.4\,m)^{2}}{-2\cdot (14.8\,m)\cdot (21.4\,m)}

L ≈ 62.464°

Then, we get the distance between points M and N by the law of the cosine once again:

MN = \sqrt{(7.4\,m)^{2}+(10.7\,m)^{2}-2\cdot (7.4\,m)\cdot (10.7\,m)\cdot \cos 62.464^{\circ}}

MN ≈ 9.8 m

By using <em>triangle</em> properties and the law of the cosine twice, we find that the distance between points M and N is approximately 9.8 meters.

To learn more on triangles: brainly.com/question/2773823

#SPJ1

6 0
2 years ago
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