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3 years ago

What is a solution of 1/4+x=0?

Mathematics

2 answers:

vodomira [7]3 years ago

8 0

<span> 1/4+x=0
Subtract 1/4 from both sides
Final Answer: x= -1/4</span>

sesenic [268]3 years ago

7 0

We have $\frac{1}{4}+x=0
$ Subtract x to both sides $\frac{1}{4}=-x$ Divide both sides by -1
- $\frac{1}{4}=x$

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Which of the following is the best estimate of the direction of the given vector?

notka56 [123]

Answer:

The direction of the given vector is 45° N of W

Step-by-step explanation:

* Lets revise the four directions with the four quadrants

- The four directions are:

# North which represented by the positive part of y-axis

# South which represented by the negative part of y-axis

# East which represented by the positive part of x-axis

# West which represented by the negative part of y-axis

∴ The first quadrant is between the East and the North

∴ The second quadrant is between the West and the North

∴ The third quadrant is between the West and the South

∴ The fourth quadrant is between the East and the South

* The direction of any vector is tan Ф, where Ф is the angle between

the vector and the x-axis, then:

- The direction of North of East is 45° ⇒ first quadrant

- The direction of North of West is 45° ⇒ second quadrant

- The direction of South of West is 45° ⇒ third quadrant

- The direction of South of East is 45° ⇒ fourth quadrant

* Now lets solve the problem

∵ The direction of the vector is between the North and the West

(its vertex in the second quadrant)

∴ Its direction is 45° North of West

* The direction of the given vector is 45° N of W

7 0

3 years ago

A store is advertising a sale with 15% off all prices in the store. Sales tax is 8%. Which equation will correctly determine the

hoa [83]

I think the answer is c beacause you have to multiply to get the answer

4 0

3 years ago

Ms. Anguiano is enjoying a bicycle ride on a country road

GalinKa [24]

Answer:

The rate is 13 miles per hour

Step-by-step explanation:

* Lets explain how to solve the problem

- Jim lives three miles east of State College

- At noon, he leaves his house and begins to walk due east at a

constant speed of 2 miles per hour

- Annie lives four miles north of State College

- At noon, she leaves her house and begins to bicycle due north at a

constant speed of 8 miles per hour

- The east is perpendicular to the north

* Lets solve the problem

∵ At noon means 12 p.m

∵ They moved till 1 p.m

∵ Jim walked for 1 hour and Annie bicycled for 1 hour

∵ The rate of Jim is 2 miles per hour

∵ The rate of Annie is 8 miles per hour

- The distance = rate × time

∴ Jim walked = 2 × 1 = 2 miles

∴ Annie bicycled = 8 × 1 = 8 miles

- Lets calculate the distance of Jim from the State College till his

position at 1 p.m

∵ Jim lives three miles east of State College

∴ His distance at 1 p.m = 3 + 2 = 5 miles east

- Lats calculate the distance of Annie from the State College till her

position at 1 p.m

∵ Annie lives four miles north of State College

∴ Her distance at 1 p.m = 4 + 8 = 12 miles North

- Lets find the distance between them at 1 p.m

∵ The north ⊥ east

- Use Pythagoras Theorem to find the distance

∴ The distance = √(5² + 12)² = √(25 + 144) = √169 = 13 miles

- The rate = distance/time

∵ The distance between them is 13 miles in 1 hour

∴ The rate = 13/1 = 13 miles per hour

* The rate is 13 miles per hour

6 0

4 years ago

How do i graph -2x+5.

vichka [17]

It is a nice linear equation. Remember y=mx+b
b is the y intercept you'll see
m is the slope rise over run
I don't like giving answers away but I am ready to help!

8 0

3 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

3 years ago