Check the picture below.
make sure your calculator is in Degree mode.
Suppose that receiving stations X, Y, and Z are located on a coordinate plane at the points (6,2), (negative 2,negative 4
), and (negative 10,4), respectively. The epicenter of an earthquake is determined to be 5 units from X, 5 units from Y, and 13 units from Z. Where on the coordinate plane is the epicenter located?
1 answer:
Answer:
(2,-1)
Step-by-step explanation:
A graph is useful here. Points X and Y have coordinate differences of ...
X -Y = (6, 2) -(-2, -4) = (6+2, 2+4) = (8, 6)
Then the distance between X and Y is ...
d = √(8² +6²) = √100 = 10
The point 5 units from X and from Y is the midpoint of XY:
E = (X +Y)/2 = ((6, 2) +(-2, -4))/2 = (4, -2)/2 = (2, -1)
The epicenter is (2, -1).
_____
The graph shows circles of radius 5 around X and Y, and a circle of radius 13 around Z. The circles intersect at the point (2, -1), the epicenter.
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Answer:
B 12.375 is the answer
Step-by-step explanation:
<u>Key skills needed: Fraction to Decimal Conversion</u>
1) The mixed number that is in the question is -->
2) We need to find 12 and 3/8 as a decimal.
This means it would be 12."something"
We need to find out what as a decimal is.
3) To do this, we do 3 ÷ 8 (to find the decimal form of a fraction, you do the numerator divided by the denominator).
4) Check the image I posted to see how I did 3 ÷ 8.
5) Well based on the division, 3 divided by 8 is 0.375
This means that
Therefore 12.375 is your answer
<em>Hope you understood and have a nice day!! :D</em>
