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Vadim26 [7]
3 years ago
6

Find the value of 58-9x

Mathematics
1 answer:
Yuri [45]3 years ago
5 0
You cannot have an answer to this because it is not an equation
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The cost of the fruit is given by the function y= 3x+1, where x is the number of fruits and y is the total cost. Find the
Elza [17]

Answer:

The answer is the second option: {4, 7, 10...}

8 0
2 years ago
An investor obtains a balloon mortgage with the terms shown below.
Flauer [41]

9514 1404 393

Answer:

  a.  $3,455.20

Step-by-step explanation:

The monthly payment is given by the amortization formula:

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

for loan amount P at annual rate r for t years.

For this mortgage, we use P = $530,000, r = 0.068, t = 30.

  A = $530,000(0.068/12)/(1 -(1 +0.068/12)^(-360)) ≈ $3,455.20

The monthly payment is $3,455.20.

_____

<em>Additional comment</em>

In 7 years, the balloon payment will be $481,559.91.

6 0
3 years ago
Find the area of the triangle
kupik [55]
Area = 1/2 * base * height 
 = 1/2 * 20 * 6
 = 1/2 * 120
 = 60 ft^2
6 0
3 years ago
How do I do this?<br>*Look at the directions in the photo*​
lora16 [44]

Answer:

Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2

Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
2 years ago
The overhead reach distances of adult females are normally distributed with a mean of 202.5 and standard deviation of 8 cm. a. F
Lorico [155]

Answer:

HSDHJSDHJS

Step-by-step explanation:

4 0
3 years ago
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