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svp [43]
3 years ago
10

(50 points) At a certain high school, 15 students play stringed instruments and 20 students play brass instruments. Five student

s play neither stringed nor brass instruments. What is the probability that a randomly selected student plays both a stringed and a brass instrument?
Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

Step-by-stepP(A\cup B)= 0.875

From the diagram, none of the students play both instruments.

This means the two events are mutually exclusive.

P(A\cup B)=P(A)+P(B)

The number of people playing instruments is 20.

P(A\cup B)= \frac{20}{40}  +  \frac{15}{40}

P(A\cup B)= \frac{35}{40}

P(A\cup B)= 0.875

UHHH HI BRAINLIESY HACKS LOL :))((()()()(()(()()()()

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PtichkaEL [24]

Answer:

R V

1  9π in³ 

2  36π in³

3  81π in³

Step-by-step explanation:

For, r = 1

V = π(1)²9 = 9π in³

For, r = 2

V = π(2)²9 = 4*9π in³ = 36π in³

For r = 3

V = π(3)²9 = 9*9π in³ = 81π in

R V

1  9π in³ 

2  36π in³

3  81π in³

6 0
3 years ago
Compare and contrast the relative frequency for the whole table in part B with the two-way frequency table given in the activity
PIT_PIT [208]

The way to convert counts into relative frequencies in a Two Way Relative Frequency Table is to divide the count by the total number of items

<h3>What is a Frequency Table?</h3>

This refers to the depiction of the number of times in which an event occurs in the form of a table.

Hence, when a two-way frequency table is used, it shows the visual representation of the possible relationship between different sets of data.

Please note that your question is incomplete as you did not provide the frequency table needed and also the trends and generalizations to find, so a general overview was given.

Read more about frequency tables here:

brainly.com/question/12134864

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3 0
2 years ago
H=-16t^2+96t+4<br>solve by factoring​
zlopas [31]

Answer:

6 plus or minus square root of 37/2

Step-by-step explanation:

Is the quadratic formula allowed or no?

4 0
2 years ago
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Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She
andreyandreev [35.5K]

Answer:

3w+45=557

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

w+33 kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

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The total weight of all boxes is

w+(w+33)+(w+12)=w+w+33+w+12=3w+45 kg

Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

3w+45=557

or

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3 0
3 years ago
$10 per pound of deli meat 3 1/2 pounds.
PSYCHO15rus [73]

The meat would end up costing $35 because you want to multiply 10*3\frac{1}{2}=35

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3 years ago
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