Answer:
0.5 in the first box and 1 or -1 in the second
Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
Answer:
3m + 2 ≤ 20
Step-by-step explanation:
Since they only have $20 and CANNOT go over it, the inequality would be ≤ 20
3m + 2 ≤ 20
Answer:
all real numbers
Step-by-step explanation:
(f + g)(x) = f(x) + g(x)
(f + g)(x) = 3x + 5 + x^2 = x^2 + 3x + 5
Answer: Choice D
