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Solnce55 [7]
4 years ago
5

$1400 principal earning 6%, compounded semi-annually, after 10 years?

Mathematics
1 answer:
Alina [70]4 years ago
6 0
Assuming future value of the principal is required.

P=1400
i=0.06/2=0.03
n=10*2=20
Future value
=P(1+i)^n
=1400(1.03)^30
=2528.56


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A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation A pizza delivery company buys
zubka84 [21]

Answer:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

\mu = 34 represent the mean

\sigma= 5 represent the deviation

We have a sample size of n = 54 and we want to find this probability:

P(33.3 < \bar X< 34.3)

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

7 0
4 years ago
Explain why the x-coordinates of the points where the graphs of the equations y = 2−x and y = 8x+4 intersect are the solutions o
Luda [366]
Part 1)
We have two lines:  y = 2-x   and   y = 8x+4
Given two simultaneous equations that are both required to be true.
the solution is the points where the lines cross
Which is where the two equations are equal
Thus the solution that works for both equations is when
2-x = 8x+4
because
where that is true is where the two lines will cross and that is the common point that satisfies both equations.

Part 2) Make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3

see the attached table
The table shows that none of the integers from [-3,3] work because in no case does
<span>2-x = 8x+4
</span>
To find the solution we need to rearrange the equation to the form x=n
2-x =8x+4
8x+x=2-4
9x=-2
x=-2/9

 The only point that satisfies both equations is
where
 x = -2/9
Find y:
   y = 2-x  = 2 - (-2/9) = 2 + 2/9 = 20/9
Verify we get the same in the other equation
y = 8x+4   =  8(-2/9) + 4 = 20/9 
Thus the only actual solution, being the point where the lines cross,
 is the point (-2/9, 20/9)------> (-0.22,2.22)

Part 3) how can you solve the equation 2−x = 8x+4 graphically?
<span>The point on the graph where the lines cross is the solution to the system of equations
</span>
using a graph tool
see the attached figure

the solution is the point (-0.22,2.22)

4 0
4 years ago
2 Points
inn [45]
Technically this is a line segment, but since that is not an option. choose the answer “line”
3 0
3 years ago
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Use the alternative form of the dot product to find u · v.
vodka [1.7K]

Answer:

Step-by-step explanation:

u = 45

v = 30

Angle between them, θ = 5π / 6 = 150°

(a) The formula for the dot product is given by

\overrightarrow{u}.\overrightarrow{v}= u v Cos\theta

\overrightarrow{u}.\overrightarrow{v}= 45 \times 30 \times Cos150

\overrightarrow{u}.\overrightarrow{v}= -1169.13

(b) \overrightarrow{u}=Cos\frac{\pi }{3}\widehat{i}+Sin\frac{\pi }{3}\widehat{j}

\overrightarrow{u}=0.5\widehat{i}+0.866\widehat{j}

\overrightarrow{v}=Cos\frac{2\pi }{3}\widehat{i}+Sin\frac{2\pi }{3}\widehat{j}

\overrightarrow{v}=-0.707\widehat{i}+0.707\widehat{j}

Let the angle between them is θ

The formula in terms of the dot product is given by

Cos\theta =\frac{\overrightarrow{u}.\overrightarrow{v}}{u v}

u=\sqrt{0.5^{2}+0.866^{2}}=1

v=\sqrt{-0.707^{2}+0.707^{2}}=1

Cos\theta =\frac{0.5 \times (-0.707) + 0.866 \times 0.707)}{1\times 1}

Cos\theta=0.2587

θ = 75°

(c) \overrightarrow{u}=1\widehat{i}+4\widehat{j}+8\widehat{k}

u=\sqrt{1^{2}+4^{2}+8^{2}}=9

Cos\alpha =\frac{1}{9}

Cos\beta =\frac{4}{9}

Cos\gamma  =\frac{8}{9}

7 0
4 years ago
After running a marathon, Marcel’s heart beat rate was 80 beats in twenty seconds. What was his heart rate for 1 second?
boyakko [2]

Answer

4 beats

Step-by-step explanation:

80 divided by 20= 4 beats per second

5 0
4 years ago
Read 2 more answers
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