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Scorpion4ik [409]
2 years ago
10

I don’t know how to do this. Ignore my work it’s probably wrong. Please help.

Mathematics
1 answer:
wariber [46]2 years ago
6 0

Check the picture below.

A)

well, we start off by making a table of values for the function, with a few "t" values, as you see in the picture, then graph those points to get the graph.

B)

at t = 0, h(0) = 98, and at t = 1, h(1) = 82, so it went from 98 to 82, for a difference of 16.

C)

at t = 1, h(1) = 82, and at t = 2 h(2) = 34, so it went from 82 to 34, for a difference of 48.

does it fall the same distance on both intervals? well, they're different, so nope.

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Serggg [28]

y = (x - 2)(x + 5)    First I would multiply (x - 2) and (x + 5) together

y = x² + 5x - 2x - 10

y = x² + 3x - 10


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y = 0² + 3(0) - 10

y = -10

(0, -10)   [this is the y-intercept (the y value when x = 0)]


Your answer is Graph A because the y-intercept is (0,-10)

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Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.
Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

                                                                      = 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$.

Therefore, the area of the square is given by $\text{(side)}^2$

                                                                         = $(r\sqrt 2)^2$

                                                                         $= 2 r^2$

                                                                         $= 2 (1)^2$

                                                                         $=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

7 0
3 years ago
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nika2105 [10]

\frac{1}{2}y\leq -7     Multiply 2/1 or 2 on both sides to get "y" by itself

(2)\frac{1}{2}y\leq -7(2)

y ≤ -14


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