Let x be the old price
X= 1200$
The price decreased 20% after 1 year to become price y :
Y= 0.8x
= 0.8 (1200)
= 960$
In the year after y also decreased 20% to be price y’:
Y’= 0.8y
= 0.8 (960)
= 768 $
The price y’ then decreased 20% to become price y’’:
Y’’ = 0.8 y’
= 0.8 (768)
= 614.4 $
Then the price will be 614.4 $ after 3 years
Adding both equations cancels y:
<span>4x + 8y = 16
</span><span>4x - 8y = 0
-----------------+
8x = 16 => x=2
filling in x=2 in the first equation gives:
4*2 + 8y = 16 => 8y = 8 => y=1
So (2,1) is the (x,y) pair that solves the two equations. Answer C.</span>
: <span> you have to solve for y. So if you do that you get y= -2/3x + 6
graph according to y=mx + b
b is y intercept, so the graph crosses the point (0, 6)
m is the slope and slope is rise over run. So go down 2 and right 3 from (0,6) as many times as you need to fill up the graph.
Then go up 2 and left 3 from (0,6) as many times as you need to fill the graph.
Put arrows at each end of your line to show that it's a line. </span>
Answer:
sin(theta) + cos(theta) = 0
sin(theta) = -cos(theta)
sin(theta)/cos(theta) = -1
tan(theta) = -1
theta = - 45° ± k·180°
Answer:
Step-by-step explanation:
So 5.40 divided by 12
