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nika2105 [10]
3 years ago
10

Dylan has $14.00 to spend at the book fair. He decides to buy two paperbacks for $4.50 each. Then, he sees some sticker books. A

t most, how much can he spend on sticker books?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer: 5 dollars

Step-by-step explanation:

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Transitive property: if ____=-11^3 and -11i^3=11i then _____=11i
Semenov [28]

Answer:

if -11i^3 =-11^3 and -11i^3=11i then -11^3=11i

if I'm wrong pls correct me but I'm pretty sure this is

5 0
2 years ago
1+1+1+1+1+1+1+1+1+1 who would like to be my friend 1+1+1+1+1+1+1+1
ycow [4]

Answer:

i would :)))))

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A triangle has sides of 6 m 8 m and 11 m is it a right-angled triangle?​
rewona [7]

Answer:

No

Step-by-step explanation:

If we use the Pythagorean theorem, we can find if it is a right triangle. To do that, set up an equation.

6^{2}+8^{2}=c^2

If the triangle is a right triangle, c would equal 11

Solve.

36+64=100

Then find the square root of 100.

The square root of 100 is 10, not 11.

So this is not a right triangle.

I hope this helps!

4 0
3 years ago
The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5
Phantasy [73]

1. Given that the width of the rectangle is x, and the area of the rectangle may be represented by the equation x^2 + 5x = 300, we can solve this equation for the width (x) as such:

x^2 + 5x = 300

x^2 + 5x - 300 = 0 (Subtract 300 from both sides)

(x - 15)(x + 20) = 0 (Factorise x^2 + 5x - 300)

From this, we get: x = 15 or x = -20

Since the width must be a positive length (ie. more than 0), -20 would be an invalid answer in the given context and thus the width is given by x = 15.

2. If we know that the length is 5 inches more than the width, we simply need to add 5 to the width we found above to obtain the length:

Length = x + 5

Length = 15 + 5 = 20

Thus, the width of the rectangle is 15 inches and the length of the rectangle is 20 inches.

6 0
2 years ago
Determine whether each function is continuous at x=5. Justify your answer using the continuity test.
irakobra [83]

Answer:

2. f(x)=\frac{x^2}{x+5}

Step-by-step explanation:

When you replace x=5 into those functions you obtain:

1. f(x)=\sqrt{x^2-36} = \sqrt{5^2-36} = \sqrt{-11} \\2. f(x)=\frac{x^2}{x+5}=\frac{5^2}{5+5}=\frac{25}{10}

We can see that the function number 1, when the x=5 is replaced, falls into the imaginary numbers or complex domain, so the function is not continuous in the real domain.

On the other hand, the second function falls into the real domain whe x=5 is replaced, so the function is continuous in the real domain!

I hope you understand!

6 0
3 years ago
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