Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
X y
-2 -3
-1 -1
0 1
1 3
2 5
i can’t graph it, but i hope this helps
Answer:
D
Step-by-step explanation:
For it to be a function, every x value must have 1 unique y value ONLY.
In option A, you can see that the x value of 1 has 2 y values, 1 & 5. So it's not a function.
In option B, you can see that the x value of 0 has 2 y values, 0 & -4. Moreover, the x value of 4 also has 2 y values, 2 & -2. So it's not a function.
In option C, you can see that the x value of -2 has 2 y values, 4 & -4. This is not a function as well.
In option D, each x value has a unique y value that are different. So this is a function.
Answer is option D.
You can ask and answer questions
Answer:
320,000
Step-by-step explanation: