Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality
red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3
there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality
summary :
ur 2 inequalities are :
x + 2y < = 5 and 3x + y < = 4
4y(3y + 9)
12y + 36
36 ÷ 12=x=3
The perimeter of a rectangle is (2 lengths) plus (2 widths).
If one side is missing, then it sounds like you still have enough information
to know what the length and the width are. Just take each number and use
the first line up there /\ to calculate the perimeter with them.
