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Rufina [12.5K]
3 years ago
13

May someone help me with this :)

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

Perimeter is 30 and area is 32

Step-by-step explanation:

7+8+7+8= 30 and A= BH so 8 x 4 = 32

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When NB = 12 ft, find the area of the region that is NOT shaded. Round to the nearest tenth.
Alborosie
If this item has the same picture on the same question posted before, the following will be the data.

Given: NB = 12 ft, Angle-120°<span>
Asked: area of the region that is not shaded.
Substitute the given values in the equation in finding the area of a circle.
</span>A = πr² 
<span>A = ⅔π(12 ft)² </span>
<span>A = 96π ft² 
(Since </span>120° is 1/3 of the circle. it is then understood that the unshaded parts must be 2/3 of the circle.)
Since you already have the area, find the area of the triangle to add it to the area of the circle to find the area of the unshaded part. By using a handy trigonometry, you can tell that their will be 2 triangles of 12 ft (if you are going to divide 120° angle). From this, you'll see that there will be one of the smaller triangles having a <span> the height of 6 ft and the base is 6√3 ft. Substitute the values.</span>
A = ½bh 
<span>A = ½(6 ft)(6√3 ft) * 2 </span>
<span>A = 36√3 ft² 
</span>
Add them up and you will have the exact answer  96π + 36√3 ft², when rounded to the nearest tenth, you will have <span> 364 ft². </span>

6 0
3 years ago
What is 5 1/2 minus 3 1/4
Brut [27]
5 1/2 - 3 1/4

11/2 - 13/4

22/4 - 13/4 = 9/4

your answer is 2 1/4

hope this helps
7 0
4 years ago
Read 2 more answers
What’s step one to solving equations with decimals
dexar [7]
Line them up by the decimal point
4 0
3 years ago
Mike has two containers, One container is a rectangular prism with width 2 cm, length 4cm, and height 10cm. The other is a cylin
saul85 [17]

so, we know both the rectangular prism and the cylinder got filled up to a certain height each, the same height say "h" cm.

we know the combined volume of both is 80 cm³, so let's get the volume of each, sum them up to get 80 then.


\bf \stackrel{\stackrel{\textit{volume of a}}{\textit{rectangular prism}}}{V=Lwh}~~ \begin{cases} L=length\\ w=width\\ h=height\\[-0.5em] \hrulefill\\ L=4\\ w=2\\ \end{cases}~\hspace{2em}\stackrel{\textit{volume of a cylinder}}{V=\pi r^2 h}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{prism's volume}}{(4)(2)(h)}~~+~~\stackrel{\textit{cylinder's volume}}{(\pi )(1)^2(h)}~~=~~80 \\\\\\ 8h+\pi h=80\implies h(8+\pi )=80\implies h=\cfrac{80}{8+\pi }\implies h\approx 7.180301999

7 0
4 years ago
I need help ASAP!! ​
kotegsom [21]

Answer:

chile you better pray to god....

Step-by-step explanation:

8 0
3 years ago
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