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Fiesta28 [93]
3 years ago
5

One of the factors of p^5 - 144p^3 is A. P^3 B. P + 12 C. P - 12 D. All of the above

Mathematics
2 answers:
valina [46]3 years ago
8 0
The answer would be (D) All of the above

The factors are below
p^3(p^2-144)
p^3(p-12)(p+12)
MAVERICK [17]3 years ago
6 0
<span>p^5 - 144p^3
= p^3(p^2 - 144)
= p^3(p + 12)(p - 12)

answer
</span><span>D. All of the above</span>
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Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
2 years ago
The total length of a beach is 18.2 kilometers. If lifeguards are stationed every 0.07 kilometers, including one at the end of t
WARRIOR [948]

There would be 260 lifegurads

The easy way is to divide 18.2 by 0.07 to get your answer

If my answer is wrong pls let me know i try my best to edit and make it right

4 0
3 years ago
$2,000 at 9% simple interest; deposit $1,600
earnstyle [38]

oops sorry.

180 was the 9% interest.

4 0
3 years ago
The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea
Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that P(A \cap B) = 0.03

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that P(A) = 0.03 + 0.7 = 0.73

What is the probability of the following event: He has lung disease given that he does not smoke?

P(B|A) = \frac{0.03}{0.73} = 0.0411

4.11% probability that he has lung disease given that he does not smoke

5 0
3 years ago
Write an equation in slope intercept form for the line with slope 1/2 and y-intercept -2
forsale [732]
Y=1/2x + -2 i think
3 0
3 years ago
Read 2 more answers
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