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3 years ago

I really need help i will rate you branliest

Mathematics

1 answer:

AlexFokin [52]3 years ago

8 0

<h3>Answer: $14,137.30</h3>

Work Shown:

A = P*(1+r)^t

A = 21450*(1+(-0.08))^5

A = 21450*(1-0.08)^5

A = 21450*(0.92)^5

A = 21450*0.6590815232

A = 14137.29867264

A = 14,137.30

Notice how I used a negative r value to indicate depreciation rather than growth.

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3 years ago

3.50 rounded to the nearest whole ounce

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3 years ago

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4 years ago

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sergey [27]

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5 0

3 years ago

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Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)

Svet_ta [14]

<h2>Answer:</h2>

$\boxed{x=1, \y=-1, \ z=2}$

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}$

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}$

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}$

Step 4: solve for z, then for y, then for x:

$\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}$

$-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}$

By substituting $y=-1 \ and \ z=2$ into the first equation, we get the $x$ . So:

$x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}$

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4 years ago

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