Answer:
one real solution
Step-by-step explanation:
We can use the discriminant to find the types of solutions
b^2 -4ac where ax^2 +bx+c=0
Since
x^2 -8x+16 =0
we know a=1 b=-8 and c=16
(-8)^2 - 4(1)(16)
64 -64 = 0
If the discriminant > 0 we have two real solutions
If the discriminant = 0 we have 1 real solutions
If the discriminant < 0 we have two complex solutions
Since it equals zero, we have one real solution