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2 years ago

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics

2 answers:

Andrej [43]2 years ago

8 0

Answer:

one real solution

Step-by-step explanation:

We can use the discriminant to find the types of solutions

b^2 -4ac where ax^2 +bx+c=0

Since

x^2 -8x+16 =0

we know a=1 b=-8 and c=16

(-8)^2 - 4(1)(16)

64 -64 = 0

If the discriminant > 0 we have two real solutions

If the discriminant = 0 we have 1 real solutions

If the discriminant < 0 we have two complex solutions

Since it equals zero, we have one real solution

Firlakuza [10]2 years ago

4 0

Answer:

One real solution because the answer is $(x-4)^{2}$

Step-by-step explanation:

$x^{2} -8x+16=\\(x-4)(x-4)$

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Which equation represents the line that passes through (-3,5) and is parallel to the graph of y= -2/3x+5

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Parallel to the graph of y = -2/3x + 5
means that it has the same slope

Rewrite
y = -2/3x + b
plug in the given coordinates to solve for b
5 = -2/3(-3) + b
5 = 2 + b
subtract 2 from both sides
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plug that back into the equation
y = -2/3x + b
y = -2/3x + 3

The answer is <span>B. y= -2/3x+3</span>

This line is parallel to y = -2/3x + 5 and it passes the point (3, 5).

Hope this helps :)

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