5x+7y=25
5x-2y=-65
subtract both of the equations
5x-5x=0
7y--2y= 7y+2y=9y
25--65=25+65=90
0+9y=90
9y=90
divide both sides by 9 to get y by itself
9y/9=90/9
cross out 9 and 9 which becomes 1*1*y=y
90/9=10
y=10
find x by using the substitution method
5x+7y=25
5x+7(10)=25
5x+70=25
move +70 to the other side
sign changes from +70 to -70
5x+70-70=25-70
5x=-45
divide both sides by 5 to get x by itself
5x/5=-45/5
cross out 5 and 5 then becomes 1*1*x=x
-45/5=-9
x=-9
answer:
(-9,10)
Please use the symbol " ^ " to denote exponentiation: 9x^6 = (___)^2.
Note that 9x^6 = 3^2*(x^3)^2. Thus,
9x^6 = (___)^2 becomes (3x^3)^2.
Then <span>9x^6 – 16y^6 = (3x^3)^2 - (4y^3)^2 = ((3x^3) - (4y^3))[(3x^3) +(4y^3)]</span>
The domain is all real numbers, the function is a variant of linear, which could be expressed in the form of y=mx+b as y = -w + 17.5, therefore all real numbers is the domain and the range.
Answer:
18
Step-by-step explanation:
6x5=30
2x8=16
8x1/2=4
30-16=14
14+4=18
