x^2 + 6xy + 8y2
4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
Combine like terms:
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)
= -x^2 + 6xy + 8y^2
Answer:
d
Step-by-step explanation:
just got 100 percent on quiz
The additive inverse of a number is that number with its sign changed.
The additive inverse of 5/8 is -5/8, so that is the value of <em>m</em>.
The sum of a number and its additive inverse is <em>zero</em>. (This is actually the definition of <em>additive inverse</em>.)
5/8 is found at 5/8 on the number line.
m is found at -5/8 on the number line.
"sum" is found at 0 on the number line.
Answer:
Step-by-step explanation:
x2 - 4x - 12 = 0
x2 - 6x + 2x - 12= 0
x(x - 6) + 2(x - 6) = 0
x + 2 = 0
x = - 2
x - 6 = 0
x = 6
Answer:
it is the blue box (not teal)
64 x 7/4 is less than 64 because 7/4 > 1
Hope this helps :)
