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Oksi-84 [34.3K]
4 years ago
6

A slice is made perpendicular to the base of a right rectangular prism, as shown in the figure. What is the shape of the resulti

ng two-dimensional cross- section? Select from the drop-down menu to correctly complete the statement. The cross-section is a .
Rectangular prism with a gray rectangle dividing the prism vertically. The rectangle is parallel to the front and back of the prism.
Mathematics
1 answer:
Elena-2011 [213]4 years ago
5 0

Answer:

A rectangle.

Step-by-step explanation:

Since the cross-section will be perpendicular to the base, it is parallel to the lateral faces of the prism. This means it will be the same shape as the lateral faces.

The lateral faces of a rectangular prism are rectangles; this means this cross-section will be a rectangle as well.

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mixas84 [53]
No. The line just has to go below ' 1 '.
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4 years ago
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Jobisdone [24]

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8 0
3 years ago
4x + y = 3 -2x + 3y = -19 what's the solution plz help
Rainbow [258]

The solution to given system of equations is x = 2 and y = -5

<em><u>Solution:</u></em>

<em><u>Given the system of equations are:</u></em>

4x + y = 3 ---------- eqn 1

-2x + 3y = -19 ---------- eqn 2

We have to find the solution to above system of equations

<em><u>We can solve the system by substitution method</u></em>

From eqn 1,

4x + y = 3

Isolate y to one side

y = 3 - 4x ----------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

-2x + 3(3 - 4x) = -19

-2x + 9 - 12x = -19

Combine the like terms

-14x = -19 - 9

-14x = -28

Divide both sides of equation by -14

<h3>x = 2</h3>

<em><u>Substitute x = 2 in eqn 3</u></em>

y = 3 - 4(2)

y = 3 - 8

<h3>y = -5</h3>

Thus the solution is x = 2 and y = -5

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%5Csqrt%7B20%7D%20-%202%5Csqrt%7B45%7D%20%2B%5Csqrt%7B5%7D%20%29%2A%5Csqrt%7B5%7D" id="TexF
nataly862011 [7]

Answer:

<h2><em><u>-15</u></em></h2>

Step-by-step explanation:

(\sqrt{20} - 2\sqrt{45} +\sqrt{5} )*\sqrt{5}

=  \sqrt{20}  \times  \sqrt{5}  - 2 \sqrt{45}  \times  \sqrt{5}  +  \sqrt{5}  \times  \sqrt{5}

=  \sqrt{100}  - 2 \sqrt{225}  +  \sqrt{25}

= 10 - 2 × 15 + 5

= 10 - 30 + 5

= 15 - 30

=<em><u> -15 (Ans)</u></em>

7 0
3 years ago
Could I get some help please?
slega [8]
Area of a Trapezoid can be defined by:
A = \frac{1}{2} ( b_{1} + b_{2} )(h)  just substitute given information
8.1 = .5( b_{1} +6.7)(1.5)
8.1 = .75(b₁ + 6.7)
8.1 = .75b₁ + 5.025
8.1 - 5.025 = .75b₁
3.075 = .75b₁
\frac{3.075}{.75} = b_{1}
4.1 = b₁
the other base is equal to 4.1
7 0
3 years ago
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