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Whitepunk [10]
4 years ago
12

If tyler spends $22 on gas what is the total distance the boys could travel?

Mathematics
2 answers:
Gre4nikov [31]4 years ago
8 0
$1.25 x 17 = $21.25
17+5=22 gallons
22 gallons x 22 miles per gallon = 484 miles
They can travel 484 miles
Shkiper50 [21]4 years ago
6 0
32.5 miles because 1.25 x 22=27.5 + 5 he already had= 32.5
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Explain how you know 21/30 is greater than 2/3
Luba_88 [7]
Simple.

to figure out if they are either: equal, greater, or smaller...

First, find a common denominator...

\frac{21}{30}

and

\frac{2}{3} * \frac{10}{10} = \frac{20}{30}

Now, we can obviously make the assumption that \frac{21}{30} is greater than \frac{20}{30}.

Thus, your answer. 

3 0
3 years ago
Read 2 more answers
Help me<br><br><br><br> If x=1/2 and y=2/3 , find the value of xy+ (x+ y)
Dima020 [189]

Answer:

3/2

Step-by-step explanation:

7 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
The profits of a company are found by subtracting the company's costs from its revenue. If a company's cost can be modeled by 14
maksim [4K]
-.0002x²+26x-120,000

hope this helped ;)
4 0
3 years ago
For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of
Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

S=\frac{a}{1-r} [Here r is less than 1]

S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

S = \frac{1}{3}

Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

3 0
3 years ago
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