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vagabundo [1.1K]
3 years ago
12

Work out the size of an exterior angle of a regular pentagon​

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

72°

Step-by-step explanation:

The sum of the exterior angles of a regular polygon = 360°

A pentagon has 5 exterior angles, thus

exterior angle = \frac{360}{5} = 72°

ycow [4]3 years ago
5 0

Answer:

Step-by-step explanation:

Regular pentagon has 5 equal sides.

Sum of exterior angles of any polygon = 360

Exterior angle of regular pentagon = 360/no. of sides

=360/5

=72

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NeTakaya

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7 0
3 years ago
Which is the correct label of the parallel lines?
liq [111]

Answer:

a ∥ b

Step-by-step explanation:

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6 0
3 years ago
In a hospital ward, there are 10 nurses and 6 doctors. 4 of the nurses and 3 of the doctors are male. If a person is randomly se
Degger [83]
Sample space is (3FD , 3MD, 4MN, 6FN) 
   
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Its C
4 0
3 years ago
Someone help me with number 3
julia-pushkina [17]
Angle ABD = 40 Degrees. Angle DBC = 50 Degrees. Because we know that a right angle ( a boxed corner ) is 90 Degrees, you add up the X's and divide by 90 to find what X is. X in this case is 10. You then multiply using X ( 10 ). 4x10 is 40 and 5x10 is 50. Thus getting your angles.
7 0
3 years ago
Read 2 more answers
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