All categories

3 years ago

Find the height, x, of the tree. 20 points for this question

Mathematics

1 answer:

Mars2501 [29]3 years ago

3 0

Answer:

70.83

Step-by-step explanation:

srr if incorrect

You might be interested in

Stuck on this problem.. Help needed! (will mark as brainliest)

vazorg [7]

Answer: 14.8
Explanation: You’re trying to find the hypotenuse using the two legs that you have. The formula to find hypotenuse is a^2+b^2=c^2. You are trying to find c^2. So it would be 10^2+11^2=c^2. 10^2 is 100 and 11^2 is 121 and 100+121 is 221. Then you would square root 221 and get 14.8 for the hypotenuse.

3 0

3 years ago

I need help on this what is RS

lana [24]

Answer:

Step-by-step explanation:

If RS=TV

5x-9=2x+3

5x-2x=3+9

3x=12

x=4

RS is 5x-9

5(4)-9

20-9

6 0

3 years ago

If x= 1/2-√3 , prove that x³-2x²-7x+5=3

prohojiy [21]

$x=\frac{1}{2}-\sqrt3\\\\x^3-2x^2-7x+5=3\\\\(\frac{1}{2}-\sqrt3)^3-2(\frac{1}{2}-\sqrt3)^2-7(\frac{1}{2}-\sqrt3)+5\\\\=(\frac{1}{2})^3-3\cdot(\frac{1}{2})^2\cdto\sqrt3+3\cdot\frac{1}{2}\cdot(\sqrt3)^2-(\sqrt3)^3-...\\\\...-2[(\frac{1}{2})^2-2\cdot\frac{1}{2}\cdot\sqrt3+(\sqrt3)^2]-\frac{7}{2}+7\sqrt3+5$

$=\frac{1}{8}-\frac{3\sqrt3}{4}+\frac{9}{2}-3\sqrt3-2(\frac{1}{4}-\sqrt3+3)-\frac{7}{2}+7\sqrt3+5\\\\=\frac{1}{8}+\frac{9}{2}-\frac{1}{2}-6-\frac{7}{2}+5-\frac{3}{4}\sqrt3-3\sqrt3+2\sqrt3+7\sqrt3\\\\=\frac{1}{8}+\frac{1}{2}-1+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{1}{2}+5\frac{1}{4}\sqrt3=\frac{1}{8}-\frac{4}{8}+5\frac{1}{4}\sqrt3\\\\=-\frac{3}{8}+5\frac{1}{4}\sqrt3\neq3$

6 0

3 years ago

Six friends go to a movie theater. In how many different ways can they sit together in a row of six empty seats?

ZanzabumX [31]

Answer:

720

I think..i hope it helps

7 0

3 years ago

Read 2 more answers

Pls help I will give u brainlest whoever is first and gets it right!

Viktor [21]

Answer:

the answer is D

Step-by-step explanation:

3 0

3 years ago