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Masteriza [31]
3 years ago
12

Outcome Payout HHH $10 HHT $3 HTH $0 HTT -$3 TTT $10 THH -$3 THT $0 TTH $0 Kara is playing a game where she flips a coin 3 times

. She wins and loses different amounts of money based on the outcomes. What is the EXPECTED VALUE for the game?
Mathematics
1 answer:
TEA [102]3 years ago
7 0
<span>Expected value is the sum of the probability of each even times the outcome of the event.

So she wins $10 with probability 2/8, $3 with probability 1/8, $0 with probability 3/8, and loses $3 with probability 2/8.

So,

E = 10(2/8) + 3(1/8) + 0(3/8) - 3(2/8)
=5/4 + 3/8 - 3/4
=7/4

<span>= $1.75
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Y = 4x – 18<br> y = -5x +9
adelina 88 [10]

Answer:

(3, -6)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 4x - 18

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<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em> [2nd Equation]:                                                                           4x - 18 = -5x + 9
  2. [Addition Property of Equality] Add 5x on both sides:                                   9x - 18 = 9
  3. [Addition Property of Equality] Add 18 on both sides:                                   9x = 27
  4. [Division Property of Equality] Divide 9 on both sides:                                  x = 3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Substitute in <em>x</em> [1st Equation]:                                                                           y = 4(3) - 18
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