Answer:
153.9
Step-by-step explanation:
Yes you could because the obtuse angle is greater than 90 degrees so if the acute angle is inside the obtuse you could get an right angle or an 90 degree angle
Answer:
19.0681
Step-by-step explanation:
Given in the question that,
angle from ted to the dog = 60° with the ground
height of ted from the ground = 16ft
To find,
distance between dog and the door of ted's building
Considering the scenario make a right angle triangle:
<h3>By using pythagorus theorem:</h3>
Tan 40 = opposite / adjacent
Tan 40 = height / distance between dog and the door
Tan 40 = 16ft / x
x = 16 / tan40
x = 19.068057
x ≈ 19.0681 (nearest to thousand)
So, the dog need to walk 19.0681ft to reach the open door directly below Ted.
Answer:
f(n)=f(n-1)+f(n-2)
f(1)=1x
f(2)=1x
Step-by-step explanation:
This is the fibonacci sequence with each term times x.
Notice, you are adding the previous two terms to get the third term per consecutive triples of the sequence.
That is:
1x+1x=2x
1x+2x=3x
2x+3x=5x
3x+5x=8x
So since we need the two terms before the third per each consecutive triple in the sequence, our recursive definition must include two terms of the sequence. People normally go with the first two.
f(1)=1x since first term of f is 1x
f(2)=1x since second term of f is 1x
Yes, I'm naming the sequence f.
So I said a third term in a consecutive triple of the sequence is equal to the sum of it's two prior terms. Example, f(3)=f(2)+f(1) and f(4)=f(3)+f(2) and so on...
Note, the term before the nth term is the (n-1)th term and the term before the (n-1)th term is the (n-2)th term. Just like before the 15th term you have the (15-1)th term and before that one you have the (15-2)th term. That example simplified means before the 15th term you have the 14th and then the 13th.
So in general f(n)=f(n-1)+f(n-2).
So the full recursive definition is:
f(n)=f(n-1)+f(n-2)
f(1)=1x
f(2)=1x
