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2 years ago

* * +:) help .........

Mathematics

1 answer:

adoni [48]2 years ago

8 0

1. -11 2.-3

Make sure to simplify the equation..

example: 3(2x - 7) = 6x - 21

because 3 x 2 = 6 and 3 x 7 = 21

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A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

How many three-digit positive integers have three different digits?

olganol [36]

648 is the three-digit positive integers have three different digits

According to the statement

we have given that there are three positive digit number are formed with three distinct digits.

And we have to find that the how many words are formed with distinct numbers.

So, to solve this type of problem the Combination formula is best.

Because it provides the all possibilities that from how many ways numbers are formed.

So, from a combination formula

here we take 9 two times because first time when we let a number then remaining numbers are 9. and second time remaining numbers are also 9 because we let the distinct number but for third number there will be a probability that choosing number will be same.

So, Three digit positive number become from 9*9*8 =648

So, 648 is the three-digit positive integers have three different digits.

Learn more about COMBINATION here brainly.com/question/4658834

#SPJ1

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2 years ago

Plasserea numbers in ascending Order

kherson [118]

Answer:

the pic is 't clear

Step-by-step explanation:

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3 years ago

Designer Dolls, Inc. found that the number N of dolls sold varies directly with their advertising budget A and inversely with th

GREYUIT [131]

I think 104,000 is the answer because when 26,000 is double it's 52,000 so I doubled 52,000 and 104,000 is what I got.

5 0

3 years ago

Read 2 more answers

si en una encuesta el resultado fue 75% la mayoria y en segundo fue 18.2% y el ultimo lugar fue 6.8% que operaciones tengo que h

Harman [31]

The operation you need to use is divide.

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3 years ago