A.
Variation in species --> natural selection --> differential reproduction --> heredity --> evolution
B.
Heredity --> variation in species --> differential reproduction --> natural selection --> evolution
C.
Variation in species --> differential reproduction --> heredity --> natural selection --> evolution
Answer:
The correct answer is b. all tall
Explanation:
If the genotype of one parent for height is Tt and another parent is TT then after the fusion of gamete all the offspring will show tall phenotype because all the offspring will have at least one allele of tall character.
T t
T TT Tt
T TT Tt
So after cross two phenotype would be homozygous dominant for tall character and the other two will be heterozygous dominant for tall character. Therefore all the offspring would be tall.
Beneficial mutations: HIV resistance, lactose tolerance & trichromatic vision
Answer:
prokaryotic genomic DNA is attached to the plasma membrane in the form of a nucleoid, in contrast to eukaryotic DNA, which is located in a nucleus . Prokaryotic contain circular DNA in addition to smaller, transferable DNA plasmids. Eukaryotic cells contain mitochondrial DNA in addition to nuclear DNA.
Answer:
8%
Explanation:
DNA is a double-stranded molecule made up of nucleotides: A, T, G, and C. According to Chargaff, A + T + G + C = 100%, where Adenine (A) pairs with Thymine (T) while Guanine (G) pairs with Cytosine (C).
Since G pairs with C and A with T, there must be equal proportions of each nuceleotide pair i.e. A=T, G=C
If C= 42%, G is also 42%
We then have, 42 + 42 + A + T = 100
84 + A + T = 100
A + T = 100 - 84
A + T = 16%
If A and T is collectively 16% and each must contain equal proportion, therefore, A=T = 16/2 = 8%.
Hence, proportion of Adenine and Thymine in that DNA is 8%.
