Add or Subtract to Simplify: (x5 + x3) - (6x - x3 + 6x5)
1 answer:
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Answer: Choice D
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Explanation:
The left portion is the interval (-∞, -2)
This is a shorthand way of saying
The curved parenthesis says "do not include this endpoint as part of the solution set". Note the open hole at x = -2 in the diagram.
In contrast, the value x = 4 is included (due to the filled in circle), so we use a square bracket for this endpoint. Therefore, the right-hand portion is represented by [4, ∞) which translates to
Negative and positive infinity will always use a parenthesis, and never a square bracket. This is because we can only approach infinity but never reach it, so we cannot include it as an endpoint.
All of this builds up to the full interval notation to be
The only square bracket is near the 4; everything else is a curved parenthesis. This is why choice D is the final answer.
Answer:
The slopes are
Therefore, the equations are equations of <u> Perpendicular Lines .</u>
Step-by-step explanation:
Given:
......................Equation ( 1 )
..............Equation ( 2 )
To Find:
Slope of equation 1 = ?
Slope of equation 2 = ?
Solution:
On comparing with slope point form
Where,
m = Slope
c = y-intercept
We get
Step 1.
Slope of equation 1 = m1 =
Step 2.
Slope of equation 1 = m2 =
Step 3.
Product of Slopes = m1 × m2 =
Product of Slopes = m1 × m2 = -1
Which is the condition for Perpendicular Lines
The slopes are
Therefore, the equations are equations of <u> Perpendicular Lines . </u>
Answer:
OPTION A: 2x + 3y = 5
Step-by-step explanation:
The product of slopes of two perpendicular lines is -1.
We rewrite the given equation as follows:
2y = 3x + 2
⇒ y =
The general equation of the line is: y = mx + c, where 'm' is the slope of the line.
Here, m = .
Therefore, the slope of the line perpendicular to the line given = because
.
To determine the equation of the line passing through the given point and a slope we use the Slope - One - point formula which is:
y - y₁ = m(x - x₁)
The point is: (x₁, y₁) = (-2, 3)
Therefore, the equation is:
y - 3 = (x + 2) $
⇒ 3y - 9 = -2(x + 2)
⇒ 3y - 9 = -2x - 4
⇒ 2x + 3y = 5 is the required equation.