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3 years ago

What is the domain of the function

Mathematics

1 answer:

Svet_ta [14]3 years ago

7 0

Answer:

The answer would be D, 0 < x < 4

Step-by-step explanation:

Because Domian is left to right of a function, so left to right would be 0 to 4

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Solve P = 2(1 + w) for I

Paraphin [41]

Answer:

Step-by-step explanation:

2(l + w) = P

l + w = P/2

l = P/2 - w

Option 2

5 0

3 years ago

Simplify cos^2 A/1+sin A

Stels [109]

Answer:

$\displaystyle \frac{\cos^2(A)}{1+\sin(A)}=1-\sin(A)$

Step-by-step explanation:

We want to simplify:

$\displaystyle \frac{\cos^2(A)}{1+\sin(A)}$

Recall the Pythagorean Identity:

$\sin^2(A)+\cos^2(A)=1$

So:

$\cos^2(A)=1-\sin^2(A)$

Substitute:

$\displaystyle =\frac{1-\sin^2(A)}{1+\sin(A)}$

Factor. We can use the difference of two squares pattern:

$\displaystyle =\frac{\left(1-\sin(A))(1+\sin(A))}{1+\sin(A)}$

Cancel. Hence:

$\displaystyle \frac{\cos^2(A)}{1+\sin(A)}=1-\sin(A)$

7 0

2 years ago

-1/2x+2=-x+7 i need to know

ludmilkaskok [199]

$= \frac{ - 1}{ \: \: 2} x + 2 = x + 7$

$= \frac{ - 1}{ \: \: \: 2} x + 2 - x = 7$

$= \frac{ - 3}{ \: \: \: 2}x + 2 = 7$

$= \frac{ - 3}{ \: \ \: 2}x = 7 - 2$

$= \frac{ - 3}{ \: \: \: 2} x = 5$

$x = 5 \: \div \frac{ - 3}{ \: \: \: 2}$

$x = 5 \times \frac{ \: \: \: 2}{ - 3}$

$x = \frac{ - 10}{ \: \: \: 3}$

$∴ \frac{ - 1}{ \: \: \: 2} \times \frac{ - 10}{ \: \: \: 3} = \frac{ - 10}{ \: \: \: 3} + 7$

6 0

3 years ago

the volume of a cylindrical tank is 936cubic meter. if its height is 6 meter determine the base area of the tank

vladimir2022 [97]

Answer:

156 square m

Step-by-step explanation:

$volume \: of \: cylindrical \: tank \\ = area \: of \: base \times height \\ \\ 936 = area \: of \: base \times \: 6 \\ \\ area \: of \: base = \frac{936}{6} \\ \\ area \: of \: base = 156 \: {m}^{2}$

6 0

3 years ago

A rancher needs to enclose two adjacent rectangular corrals, one for cattle and one for sheep. If the river forms one side of t

Serga [27]

Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!

5 0

2 years ago