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3 years ago

HELP ME PLEASE!!!!!!!!

Mathematics

2 answers:

just olya [345]3 years ago

6 0

The answer is C. NMP=NRQ

kirill115 [55]3 years ago

5 0

The awnser is A NPM =NQR

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Find the sum of the first six terms of a geometric series in which a1 = 4 and r = -3: A. 729 B. -729 C. -728 D. 728 plz help

natta225 [31]

Answer:

Step-by-step explanation:

The sum to n terms of a geometric sequence is

$S_{n}$ = $\frac{a_{1}(r^n-1) }{r-1}$

Here a₁ = 4 and r = - 3, thus

$S_{6}$ = $\frac{4((-3)^6-1)}{-3-1}$

= $\frac{4(729-1)}{-4}$ = - (729 - 1) = - 728 → C

6 0

2 years ago

What is the mean of the set of data given below? 13 8 9 6 10 8

olga_2 [115]

Answer:

Mean = The numbers added up and divided by the number of numbers.

Step-by-step explanation:

= (13 + 8 + 9 + 6 + 10 + 8) / 6

= 54 / 6

= 9

The mean is 9.

8 0

3 years ago

Helen has 48 cubic inches of clay to make a solid square right pyramid with a base edge measuring 6 inches. Which is the slant h

Nikitich [7]

Answer: 5 inches

Step-by-step explanation:

Given: Volume of clay = 48 cubic inches

If we make a solid square right pyramid with a base edge a= 6 inches.

Then its base area = $a^2=6^2=36\ inches^2$

we know that volume of square right pyramid= $\frac{1}{3}\times\ a^2h$

Therefore, volume of square right pyramid made by all of clay= $\frac{1}{3}\times\ a^2h$ =48 cubic inches

$\Rightarrow\frac{1}{3}\times\ (36)\times\ h=48\\\Rightarrow12h=48\\\Rightarrow\ h=4\ inches.....\text{[Divide 12 on both sides]}$

Now, slant height $l=\sqrt{(\frac{a}{2})^2+h^2}$

$\\\Rightarrow\ l=\sqrt{3^2+4^2}\\\Rightarrow\ l=\sqrt{9+16}\\\rightarrow\ l=\sqrt{25}\\\Rightarrow\ l=5$

The slant height of the pyramid if Helen uses all the clay=5 inches

5 0

3 years ago

Read 2 more answers

A square is sometimes a rhombus

Veseljchak [2.6K]

Answer:

This would be true.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Somebody Please help Me

Firdavs [7]

19. -x-2 = 2/3x + 3
5/3 x + 3 = -2
5/3x = -5
x = -3

20. none are correct, you can double check me by plugging in the x and y values in the coordanates into the first problem none of them worked out in the first equasion so no need to test the second

21. -3 is the answer, capable of being done by using desmos

4 0

3 years ago