A. Competition amoumg large predatora
The answer is false. To explain further, let G have vertices
{v1, v2, v3, v4}, with ends between each pair of vertices, and with the mass on
the edge from vi to vj equal to I + j. Then each tree has a bottle neck edge mass
of as a minimum of 5, so the tree containing of a track through vertices v3, v2,
v1,v4 is a least bottleneck tree. It is not a least spanning tree, though, subsequently
its total mass is greater than that of the tree with edges from v1 to every
single vertex.
Umm whaleee i believe the first “life” which developed is bacteria.
for humans, we are evolved from the great apes. we are called homo sapiens
Observations syndrome is brain defect another name for observations
They aren’t common denominators
