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Juliette [100K]
3 years ago
6

What is the Area of the triangle

Mathematics
2 answers:
harina [27]3 years ago
5 0
A= 1/2bh
b= base
h= height

Natasha2012 [34]3 years ago
3 0
Area of triangle is 1/2 × base × height
so 1/2×12×10=60 sq meter !!!
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Pls helppp What are the factors of the product represented below?​
Nookie1986 [14]
No sehhzvzhgVshsjsbskSksjkdisksvsjs
6 0
3 years ago
Solve for side BA<br> (show your work)
Kipish [7]

Answer:

BA = 25.5961

Step-by-step explanation:

To solve for side BA, we need to use the correct trigonometric function that relates (from the perspective of angle B) side AC and BA.

AC is Opposite of angle B

BA is the Hypotenuse

The function we use here is Sine. Sine is:

Sin(θ) = Opposite/Hypotenuse

So we simply substitute our information to solve.

Sin(62) = 22.6/BA

BA = 22.6/Sin(62)

Typing this into our calculator we get:

BA = 25.5961

(This is rounded to 4 decimal places)

5 0
3 years ago
Please helppp!! Worth 20 points. I’ll mark brainliest if someone actually helps &gt;.
Nat2105 [25]

Answer: $25

Step-by-step explanation: 25 times 3(because there are three people) =75 - 45(the amount they spent)=30 the amount they are left with all together.

it took me awhile to answer so sorry for the wait but i hope this helps.

6 0
3 years ago
2x + 3y =10<br>x + y = 3 please do workings asap
kompoz [17]
This is system of Equations. 
<span>2x + 3y =10
x + y = 3 
</span>
x + y = 3 (multiply this by three) to get 3x + 3y = 9
2x + 3y =10
3x + 3y = 9 Subtract them

-1x = 1 
x=-1 
Now plug x back into the top equation and solve for y. 

I hope this helps! If not, let me know! Have a fantastical day!
5 0
4 years ago
Read 2 more answers
Third-degree, with zeros of 4-I,4+I and a leading coefficient of -5
Jobisdone [24]
Please use "i" for the imaginary operator, not "I."

A third degree poly would have 3 factors and 3 zeros; you've supplied only 2 zeros.  

Let's model the polynomial as y = ax^3 + bx^2 + cx + d.
We are told that the leading coefficient is -5.  Therefore, our model becomes

y = -5x^3 + bx^2 + cx + d

The two given roots are 4-i and 4+i; if either is subst. into the above equation, y takes on the value 0 (this is the meaning of "root")

Thus, if x = 4-i, 0 = -5(4-i)^3 + b(4-i)^2 + c(4-i) + d.
          If x = 4+i, 0 = -5(4+i)^3 + b(4+i)^2 + c(4+i) + d

Here we have two equations in three unknowns (b, c and d).  There's not enough info to enable us to determine all three b, c and d.

One thing you might do at this point would be to set d=0 arbitrarily, and then solve the resulting two equations (without d) for b and c.

Can you take the ball and run with it from this point on?
5 0
3 years ago
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