Answer:
Jillian is incorrect because square roots of perfect squares are rational.
Step-by-step explanation:
√25 = √(5²) = 5 - rational
25 is perfect square.
The result of multiplying the polynomials is (2x + 3) (-x + 2y - 4) = -2x² + 4xy - 11x + 6y - 12
<h3>How to multiply the
polynomials?</h3>
The polynomial expression is given as
(2x + 3) (-x + 2y - 4)
Expand the brackets in the above polynomial expression
So, we have
(2x + 3) (-x + 2y - 4) = 2x * (-x + 2y - 4) + 3 * (-x + 2y - 4)
Open the brackets in the above polynomial expression
So, we have
(2x + 3) (-x + 2y - 4) = -2x² + 4xy - 8x + -3x + 6y - 12
Evaluate the like terms in the above polynomial expression
So, we have
(2x + 3) (-x + 2y - 4) = -2x² + 4xy - 11x + 6y - 12
Hence, the solution is -2x² + 4xy - 11x + 6y - 12
Read more about polynomials at
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Answer:
x = 4.75 or 19/4 or 4 and 3/4
Step-by-step explanation:
10 - 4x = -9
-10 -10
-4x = -19
---- -----
-4 -4
x = 4.75 or 19/4 or 4 and 3/4
For (2), start with the base case. When n = 2, we have
(n + 1)! = (2 + 1)! = 3! = 6
2ⁿ = 2² = 4
6 > 4, so the case of n = 2 is true.
Now assume the inequality holds for n = k, so that
(k + 1)! > 2ᵏ
Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have
((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!
Then by our hypothesis,
(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹
and k•2ᵏ ≥ 2•2² = 8, so
k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹
which proves the claim.
Unfortunately, I can't help you with (3). Sorry!
