Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers
Answer:
Step-by-step explanation:
Light is considered to be without mass, but it has energy. According to Einstein, energy can be
equivalently presented as mass. Mass is also affected by gravity, but near planets, this effect is
so small that it can be ignored and so we say that light travels in a straight line.
The above statement does not hold true when light passes near a star. A star possesses a very
high gravity field that bends light such that the change of direction is observed.
No. If line WX would have been a tangent, the angle VWX should have been 90 degrees. If it would have been 90 degrees, using the pythagoras theorem, side VX should have been 5. But it's not 5, neither angle VWX is 90 degrees nor is the line WX a tangent to the circle
Answer: x=-4
Step-by-step explanation:
