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3 years ago

What is the square root of zero?

Mathematics

1 answer:

Lina20 [59]3 years ago

4 0

The answer is 0

hope this helps!!

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Help please

natta225 [31]

Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³

8 0

3 years ago

What is the quotient of 5.846 x 10^7 and 7.9 x 10^2 expressed in scientific notation

serg [7]

Answer:

Da answer issss...7.4 x 10^4..I tink

8 0

3 years ago

What does the fundamental theorem of algebra illustrate?

UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form $ax^{2}+bx +c=0$

Its roots are $\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Here the given equation is $2x^{2}-4x-1$ = 0

a = 2

b = -4

c = -1

If the roots are $x_{1} and x_{2}$ , then

$x_{1}$ = $\frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{24}}{4}$

= $\frac{2+\sqrt{6} }{2}$

$x_{2}$ = $\frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{8}}{4}$

= $\frac{2-\sqrt{6} }{2}$

These are the two roots of the equation.

6 0

3 years ago

Evaluate -8y+x5 when x =2 and y= -3

kkurt [141]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

One of the interior angles of a regular polygon is 144. fine the number of sides of the polygon

lora16 [44]

Answer:

Step-by-step explanation:

In any polygon

exterior angle + interior angle = 180° , thus

exterior angle + 144 = 180 ( subtract 144 from both sides )

exterior angle = 36°

The sum of the exterior angles = 360°

Thus number of sides n is calculated as

n = 360 ÷ 36 = 10

3 0

3 years ago

Read 2 more answers