Only three rectangles are needed, the one at the bottom and the two at the sides.
I hope this helps.
YOU'RE WELCOME :D
Answer:
Step-by-step explanation:
<h3><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u>:</u><u>-</u></h3>
<h3><u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u>:</u><u>-</u></h3>
<u>Solve</u><u> </u><u>for</u><u> </u><u>x</u><u>.</u>
<h3><u>According</u><u> </u><u>to</u><u> </u><u>question</u><u>:</u><u>-</u></h3>
<h3>
</h3>
[Tangent of same circle are equal]
<h3>
</h3>
<h3><u>The</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u></h3>
Answer:
1/12
Step-by-step explanation:
Let’s list out cases:
1+1:
Probability of getting 1 and 1 is (1/6)^2 = 1/36
1+2:
Probabilty of getting 1 and 2 is (1/6)^2 = 1/36 and getting 2 and 1 is (1/6)^2 = 1/36.
That is all of the cases because 1+3 and 2+2 are equal to 4. Summing it up, we get: 3(1/36) = 1/12
Hello,
Let's a=279-i with i=0 to 16
Let's b=312-i with i=0 to 16
Let's c=697-i with i=0 to 16
Let's d=708-i with i=0 to 16
I don't know how to solve this but
If n is the commun divider, it must be <√279=16.70...
Remainder must also be < n
We have to find the maximun of (a-i)∧(b-i)∧(c-i)∧(d-i) =11 (if i=4 or i=15 )
279=11*25+4
312=11*28+4
697=11*63+4
708=11*64+4
When i=15 ,n=11 but i must be<11
so only one solution n=11 and remainder=4