If the sides of the rectangle are a and b,
Area=ab=3200^2
If the side with a ft cost $2/ft and side with bft costs $2/ft
Then,
Cost = 2*2*a+2*1*b=4a+2b
At minimum cost (or critical point), the derivative of cost =0
From area, b=3200/a
Using cost equation
C=4a+2*3200/a=4a+6400/a
First derivative with respect to a;
C'(a)=4-6400/a^2=0
Then, a=+/-40 The negative value is rejected. Therefore, a=40 ft and b=3200/40= 80 ft.
Therefore, a=40 ft and b=80 ft to minimize the fencing cost.
Length is 3 times the width
So L = 3W
If L is decreased by 4m and with increased by 1m and perimeter is 66 then
2(3W - 4) + 2(W + 1) = 66
6W - 8 + 2W + 2 = 66
8W - 6 = 66
8W = 72
W = 9
L = 3 x 9 = 27
Width of rectangle = 9 m and length = 27 m
New rectangle:
Width is increase by 1 m = 9 + 1 = 10 m
Length is decreased by 4 m = 27 - 4 = 23 m
Answer
Dimensions of new rectangle are 10 m and 23 m
Answer:
The temperature drops by 5 degrees each hour.
Step-by-step explanation:
35/7=5 degrees dropped per hour.
Hope it helps!:)
Answer:
I believe it's major arc
Step-by-step explanation:
Second option on edge
