For this question, we are given a mean/average rate, that is 4 errors per page;
This suggests we need to use the Poisson distribution, so:
Let X be the random variable, the number of errors per page;
X~Po(4) ← X has a Poisson distribution with mean (λ) of 4
a)
What we want is the probability that X = 5, so we use the formula for Poisson:
= 0.156 (to 3 s.f.)
b)
What we want to find is the probability that X ≤ 5, so we have to use the cumulative tables:
P(X ≤ 5) = 0.7851
c)
What we want to find is the probability that X > 5, so we have to do a bit of manipulation and then use the cumulative tables;
The tables give values for ≤, so we cannot directly look up a value for >, thus the manipulation:
P(X > 5) = 1 - P(X ≤ 5)
= 1 - (0.7581)
= 0.2419
it is isosceles triangle as you see
so that 62 = other unknown angle
as it is a triangle interior angles sum = 180
124 + x = 180
x = 180 - 124
x = 56
9514 1404 393
Answer:
C. -2.00 m/sec
Step-by-step explanation:
The average velocity on the interval [a, b] is found by ...
m = (s(b) -s(a))/(b -a)
One end of the interval remains constant here, so we can define 'd' so that the interval is [4, 4+d]. Then the average velocity is ...
m = (s(4 +d) -s(4))/((4 +d) -4)
m = (s(4+d) -s(4))/d
The attached table shows the average velocity values on the intervals required by the problem statement. Respectively, they are ...
-1.5 m/s, -1.7 m/s, -1.9 m/s, -1.99 m/s, 2.01 m/s, 2.1 m/s, 2.3 m/s, 2.5 m/s
We expect the instantaneous velocity at d=0 to be the average of the values at d=-0.01 and d=+0.01. We estimate the instantaneous velocity at t=4 seconds to be -2.00 m/s.
Answer:
A
Step-by-step explanation: